816Bruno

Now heres a question i made for the mean,median and mode and with the anwsers
Set of data 1,4,4,6,8,9,10 MEAN:1+4+4+6+8+9+10=42 now theres 7 pieces of data so u divide 42\7=6.By the way i but it in order but next time u need to. Median well look at the data 1+5+5+6+8+9+10 and find the middle number Which is 6.

Mode well remember mode means the number that occurs the most in your set of data which in the case is 4

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Perfect square: Perfect square means all the side are all equally to each other.
Now heres my question for square roots what is the square root of 64. so what times it self that equals 64 8X8=64 so 8 is times it self and = 64 How did i get that well to make this easy i use this chart its called a perfect square chart 1x1=,2x2=4,3x3=9,4x4=16,5x5=25,6x6=36,7x7=49,8x8=64,9x9=81,10x10=100 How to solve it well 64 is between in the chart 7 and 8 but your dont have to do this on this question cause it a simple one cause 8x8=64

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Now for percent here is my question taking off 15% off a given item and then an additional 10% off the reduced price the same as taking 25% off the original price? Why or why not?

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Two Ratio and proportion questions
My Question for ratio and proportion.Create a proportion from each set of numbers only use 4 numbers from each set of numbers.Prove your answers are right. numbers 21,7,6,18,9 part 6 18=85 % total 7 24= 85 % for this u just have to cross multiply or divide 6\7=85 and 18\21=85 % now for the other chart these are your numbers. 16,2,1,21,8 Part 1 8 Whole 2 16 All you had to do is find two fractions that the same percent and 1over 2= 50 % and 8 over 16 = 50 % My other question is Duane Wade scored 12 points in 8 minutes. IF he keeps scoring at this rate how many points will he score in 48 minute game well i used a t-chart and Minute is on one side and points on other side on minutes side 12- 72 on points side 8 over 48 and what i did is i cross multiplied 12 over 48 and 8 over 72 so p\m 12\72=8\48 well every i am done and have a nice!!!!! http://816branswers.wikispaces.com/